Solusi Persamaan ln(x²) + e^x = 0 dengan Newton-Raphson
function f(x) {
return Math.log(x * x) + Math.exp(x);
}
function df(x) {
return (2 / x) + Math.exp(x);
}
function newtonRaphson(x0, tol = 1e-6, maxIter = 100) {
let x = x0;
for (let i = 0; i < maxIter; i++) {
let fx = f(x);
let dfx = df(x);
if (Math.abs(dfx) < 1e-10) {
return "Diferensial nol, metode gagal.";
}
let xNext = x – fx / dfx;
if (Math.abs(xNext – x) < tol) {
return `Akar ditemukan: ${xNext.toFixed(6)} (iterasi ke-${i + 1})`;
}
x = xNext;
}
return "Maksimum iterasi tercapai, solusi tidak konvergen.";
}
function solveNewtonRaphson() {
let initialGuess = parseFloat(document.getElementById("initialGuess").value);
let result = newtonRaphson(initialGuess);
document.getElementById("result").innerText = result;
}
